Time Speed and Distance Questions with Solutions | Set 1 (Q1 to Q10)

This set contains Time Speed and Distance Questions with Solutions — Set 1 (Q1 to Q10) covering a mix of question types and difficulty levels — from basic to advanced — exactly as asked in real competitive exams.

Solutions are written in a simple, step-by-step notebook style for easy self-study and quick understanding. Each solution is broken down step by step so even the toughest question feels easy. These questions are hand-picked for students preparing for SSC CGL, SSC CHSL, CAT, Bank PO, Bank Clerk, UPSC CSAT, Railway RRB, AMCAT, eLitmus, TCS NQT and all campus placement aptitude tests. International students preparing for GRE, GMAT, SAT, ACT, MAT and all Numerical Reasoning Tests will find these equally useful.

✏️ Attempt each question on your own first — then check the solution below.

1. A travells a distance of 180 km in 5 hr. Find his speed in m/sec ?

2. A covers 32.5 km in 5 hours. Find the distance covered by him in 8 hours.

3. A person goes from A to B at a speed of 30 km/h & returns from B to A at a speed of 10 km/h. What is the average speed for the whole journey ?

4. A boy goes to a school at a speed of 3 km/h and returns at a speed of 2 km/h. If he takes 5 hr in all. find the distance between village & school.

5. A man goes from A to B at a speed of 20 km/h and returns at higher speed. If its average speed for the whole journey is 24 km/h, at what speed he returned ?

6. In a journey of 240 km, a man covers a distance of 150 km at a speed of 75 km/h, the next 60 km distance at a speed of 100 km/h and the remaining distance at the speed of 75 km/h. Find the average speed for the whole journey.

7. A man went from Delhi to Lucknow via Bareilly by car. The distance from Delhi to Bareilly is \(\frac{3}{4}\) times the distance from Bareilly to Lucknow. the average speed from Delhi to Bareilly is \(\frac{3}{2}\) times the average speed from Bareilly to Lucknow. If the average speed for the entire journey was 56 km/h. What was the average speed from Bareilly to Lucknow ?

8. A car during its journey travells 30 minutes at a speed of 20 km/h, another 12 minutes at a speed of 50 km/h and 1 hour at a speed of 48 km/h. Find the average speed of the car ?

9. A starts his journey from Delhi to Jaipur and simultaneously B starts from Jaipur to Delhi. After crossing each other they finish their remaining journey in \(9\frac{4}{5}\) hours & 5 hours respectively. What is A’s speed if B’s speed is 35 km/h ?

10. Two persons covers the same distance at a speed of 40 km/h & 30 km/h respectively. Find the distance travelled if one person takes 15 min more than the other.

1. A travells a distance of 180 km in 5 hr. Find his speed in m/sec ?
Sol:
Speed = \(\frac{{180}}{5}\)
= 36 km/h
= 36 × \(\frac{5}{{18}}\)
= 10 m/sec       Answer

2. A covers 32.5 km in 5 hours. Find the distance covered by him in 8 hours.
Sol:

3. A person goes from A to B at a speed of 30 km/h & returns from B to A at a speed of 10 km/h. What is the average speed for the whole journey ?
Sol:
Average Speed = \(\frac{{2 \times 10 \times 30}}{{10 + 30}}\)            \(\left( {\frac{{2ab}}{{a + b}}} \right)\)
= 15 km/h         Answer

4. A boy goes to a school at a speed of 3 km/h and returns at a speed of 2 km/h. If he takes 5 hr in all. find the distance between village & school.
Sol:
Method(1):
Average speed of journey = \(\frac{{2 \times 3 \times 2}}{{3 + 2}}\) = \(\frac{{13}}{5}\)
& total time = 5 hr
∴ 2d = \(\frac{{12}}{5}\) × 5
d = 6 km         Answer

Method(2):
d = \(\frac{{{S_1} \times {S_2}}}{{{S_1} + {S_2}}} \times time\)
= \(\frac{{3 \times 2}}{{3 + 2}} \times 5\)
= 6 km          Answer

5. A man goes from A to B at a speed of 20 km/h and returns at higher speed. If its average speed for the whole journey is 24 km/h, at what speed he returned ?
Sol:
24 = \(\frac{{2 \times 20 \times x}}{{20 + x}}\)
3 = \(\frac{{5 \times x}}{{20 + x}}\)
60 + 3x = 5x
x = 30 km/h    Answer

6. In a journey of 240 km, a man covers a distance of 150 km at a speed of 75 km/h, the next 60 km distance at a speed of 100 km/h and the remaining distance at the speed of 75 km/h. Find the average speed for the whole journey.
Sol:
Avg speed = \(\frac{{total\;distance}}{{total\;time}}\)
= \(\frac{{240}}{{\frac{{150}}{{75}} + \frac{{60}}{{100}} + \frac{{30}}{{75}}}}\)
 = \(\frac{{240}}{{2 + \frac{3}{5} + \frac{2}{5}}}\)
= \(\frac{{240 \times 5}}{{15}}\)
 = 80 km/h        Answer

7. A man went from Delhi to Lucknow via Bareilly by car. The distance from Delhi to Bareilly is \(\frac{3}{4}\) times the distance from Bareilly to Lucknow. the average speed from Delhi to Bareilly is \(\frac{3}{2}\) times the average speed from Bareilly to Lucknow. If the average speed for the entire journey was 56 km/h. What was the average speed from Bareilly to Lucknow ?
Sol:

Average speed of entire journey = 56 km/h
\(\frac{{7x}}{{\frac{{3x}}{{2y}} + \frac{{4x}}{{2y}}}}\) = 56
\(\frac{{7y}}{3}\) = 56
y = 24 km/h
∴ avg speed from Bareilly to Lucknow = 2y
= 48 km/h    Answer

8. A car during its journey travells 30 minutes at a speed of 20 km/h, another 12 minutes at a speed of 50 km/h and 1 hour at a speed of 48 km/h. Find the average speed of the car ?
Sol:
Average speed = \(\frac{{20 \times \frac{{30}}{{60}} + 50 \times \frac{{12}}{{60}} + 48 \times 1}}{{\frac{{30}}{{60}} + \frac{{12}}{{60}} + 1}}\)
 = \(\frac{{10 + 10 + 48}}{{\frac{{17}}{{10}}}}\)
 = \(\frac{{68 \times 10}}{{17}}\)
 = 40 km/h     Answer

9. A starts his journey from Delhi to Jaipur and simultaneously B starts from Jaipur to Delhi. After crossing each other they finish their remaining journey in \(9\frac{4}{5}\) hours & 5 hours respectively. What is A’s speed if B’s speed is 35 km/h ?
Sol:
\(\frac{A}{{35}} = \sqrt {\frac{5}{{9\frac{4}{5}}}} = \sqrt {\frac{{25}}{{49}}} = \frac{5}{7}\)
A = 28 km/h       Answer

10. Two persons covers the same distance at a speed of 40 km/h & 30 km/h respectively. Find the distance travelled if one person takes 15 min more than the other.
Sol:
Method(1):
distance = \(\frac{{{S_1} \times {S_2}}}{{{S_1} – {S_2}}}\) × (diff. in time)
 = \(\frac{{40 \times 30}}{{40 – 30}} \times \frac{{15}}{{60}}\)
d = 30 km     Answer

Method(2):
Since distance is constant

✅ Well done on completing Set 1!

Continue practising with Time Speed and Distance Questions 11 to 20 → Set 2 or revisit the Time Speed and Distance Concept Page to strengthen your formulas and tricks before moving ahead.

Consistent practice is the key to mastering time speed and distance for SSC CGL, SSC CHSL, CAT, Bank PO, Bank Clerk, UPSC CSAT, Railway RRB, AMCAT, eLitmus, TCS NQT and international exams including GRE, GMAT, SAT, ACT, MAT and all Numerical Reasoning Tests. Want to understand the concept better? Read about Speed on Wikipedia before attempting the next set.

This page is part of our complete series of time speed and distance questions with solutions for competitive exams — covering every question type from basic to advanced so you can build speed, accuracy and confidence. Practising these questions regularly will also strengthen your core time speed and distance concept before your exam day.