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11. In two alloys A and B the ratio of zic to tin is 5:2 and 3:4 respectively. 7kg of alloy A and 21kg of the alloy B are mixed together to form a new alloy. What will be the ratio of zinc and tin in the new alloy ?
Solution:-

Method 1:In alloy A ⟹ Z T ⟹ 7 kg5 : 25 kg2 kg1In alloy B ⟹ Z T ⟹ 21 kg3 : 43912× 3× 3In new alloy ⟹ Z T ⟹ Z : T5+92+12:1 : 1Ans

method (2):

A BZ TZ T5 23 4Z Z7 21131311In new alloy zinc : alloy = 1:2zinc : tin = 1:1Ans
alternately:Tin Tin7 211 3××1311

∴ in new alloy tin : alloy = 1 : 2
zinc : tin = 1 : 1    Ans

method (3):zinc Tin CapacityAB5 2 7 kg3 4 21 kg1 1 = 1= 3A + B9125 + 9 = 142 + 12 = 14 28 kg1 : 1Ans

12. Three vessels whose capacities are in the ratio 3:2:1 are completely filled with milk mixed with water. The ratio of milk and water in the mixture of vessels are 5:2, 4:1 and 4:1 respectively. Taking \(\frac{1}{3}\) of first, \(\frac{1}{2}\) of second and \(\frac{1}{7}\) of the third mixtures, a new mixture kept in a new vessel is prepared. Find the % of water in the new mixture ?
Solution:-

method (1): Let the capacity of vessels be 3 litres, 2litres and 1 litre respectivelty.

vessel I:m w capacity5 2 31taking of the firstvessel II:m w capacity4 1 21taking of the second::vessel III:m w capacity4 1 1taking of the third:

when we mix these three vessels then in new vessel
milk = \(\frac{5}{7} + \frac{4}{5} + \frac{4}{35} = \frac{57}{35}\)
water = \(\frac{2}{7} + \frac{1}{5} + \frac{1}{35} = \frac{18}{35}\)
total new mixture = \(\frac{57}{35} + \frac{18}{35} = \frac{75}{35} = \frac{15}{7}\)
∴ % of water = \(\frac{\frac{18}{35}}{\frac{15}{7}} \times 100 = 24\% \)     Ans

method (2):milk water capacityV5 = 752 = 30VV4 = 564 = 281 = 141 = 7755now taking the quantities of the mixture as given milk water VVV25 1028 74 1∴ required % = Ans

13. 60 kg of alloy A is mixed with 100 kg of alloy B. If alloy A has lead and copper in the ratio 3:2 and alloy B has copper and tin in the ratio 1:4, then find the amount of copper in the new alloy.

solution:A Bcopper copper60 100(60+100)16013 : 51111×4 = 44 kg1435method (1):
method (2):In alloy A lead = copper = In alloy B copper = tin = ∴ In new alloy copper = 24 + 20 = 44 kg Ans

14. Two variety of tea costs Rs. 35 per kg and Rs. 40 per kg respectively are mixed in the ratio 2:3 by weight. If one-fifth of the mixture is sold at Rs. 46 per kg and remaining at the rate of Rs. 55 per kg, then find the profit percent.
Solution:

method(1):
Let 5 kg of mixture be prepared.
∴ CP of 5 kg of mixture = 2×35 + 3×40 = 190
total SP of 5 kg of mixture = 46 + 4×55 = 266
∴ profit % = \(\frac{266 – 190}{190} \times 100\) = 40%    Ans

method (2):3835 4023CP of mixture40 - 35 = 52346 55 55 - 46 = 914155 - 1 4SP of mixture

∴ profit % = \(\frac{53.2 – 38}{38} \times 100\) = 40%       Ans

15. 30 litres of a mixture contains milk & water in the ratio 4:1. Then find the amount of milk to be added to the mixture so as to have milk and water in the ratio 6:1.
Solution:

30mw6LAns