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(Q). Let Kₙ denotes the number of triangles which can b formedusing the vertices of a regular polygon of ‘n’ sides. Which one of the following could be the value of Pₙ₊₁ – Pₙ₋₁?
(a) 194                      (b) 195
(c)196                       (d) 197
Solution:-
Pₙ₊₁ = ⁿ⁺¹C₃
        =   \frac{{(n - 1)(n)(n + 1)}}{6}
Pₙ₋₁ = ⁿ⁻¹C₃
        =   \frac{{(n - 3)(n - 2)(n - 1)}}{6}

∴ Pₙ₊₁ – Pₙ₋₁   =   \frac{{(n - 1)(n)(n + 1) - (n - 3)(n - 2)(n - 1)}}{6}
                     =   \frac{{(n - 1)\{ {n^2} + n - {n^2} + 5n - 6\} }}{6}
                     = (n-1)²
Hence this value must be a perfect square, from the given option       (c) 196           Answer