(Q). Let A and B be two sets containing 2 & 4 elements respectively. The number of subsets of A×B having 3 or more elements is?
Solution:-
A×B having will have 2×4 = 8 elements
∴ Required number of ways
= 2⁸ – ⁸C₀ – ⁸C₁ – ⁸C₂
= 256 – 1 – 8 – 28
= 219 Answer
