k is the product of first 100 multiples of 15. Find the number of trailing zeros in k

(Q). k is the product of first 100 multiples of 15. Find the number of trailing zeros in k.
Solution:- k = (15×1).(15×2).(15×3)…………(15×100)
k = 15¹⁰⁰ × 100!
now highest power of 5 in 100! ⇒

Hence Number of trailing zeros in k = minimum of(Highest power of 5 in k & Highest power of 2 in k)
= 97 Answer