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(Q). In how many ways 2 + and 2 – signs are filled into 4×4 cell where each cell can contain maximum one character such that each row & column can not contain same sign ?

Solution:-

1ˢᵗ ‘+’ sign can be arrranged in ¹⁶C₁ = 16 ways
2ⁿᵈ ‘+’ sign can be arranged in ⁹C₁ = 9 ways

Since both ‘+’ signs are indistinguishable so both ‘+’sign can be arranged in \frac{{16 \times 9}}{2} = 72 ways
similarly both ‘-‘ sign can be  arranged in \frac{{16 \times 9}}{2}= 72 ways
Hence 2 ‘+’ & 2 ‘-‘ sign can be arranged in 72×72 ways.
From this valuewe have to exclude the following cases to get the final answer:-
case (i): two group (+, -) & (+, -) can be arranged in  \frac{{16 \times 9}}{2} = 72 ways
case(ii): 

(+, -) , '+' , '-'can be arranged in16 waysarrangedarranged9 ways 8 ways

Hence symbol of  case (ii) according to condition can be arranged in 16×9×8 ways
Hence required Answer is:
= 72×72 – 72 – 16×9×8
=3960 Answer