If product of factorials of n consecutive integers is a two digit number then find the maximum value of n

(Q). If product of factorials of n consecutive integers is a two digit number then find the maximum value of n.
Solution:-

0! = 1
1! = 1
2! = 2
3! = 6
4! = 24
5! = 120 → 
For maximum value of n ⇨

Hence max(n) = 4 Answer