(Q). If a! + b! + c! +d! +e! +f! +g! +h! is a two digit number then find the maximum value of a.
Solution:- For maximum value of a → value of other factorial numbers should be minimum (i.e. 1)
Hence b! + c! + d! + e! + f! + g! + h! = 7
1 1 1 1 1 1 1
& Since given expression is a two digit number. Hence maximum value of a! should be less than 99 – 7 = 92
a! ≤ 92
& Since 4! = 24
& 5! = 120
Hence maximum value of a = 4 Answer