(Q). How many factors of N = 2⁷ × 3⁷ × 5⁷ × 7⁷ ends with two zeros ?
Solution:-
In every factor 2² × 5² will be common
∴ required number of factor is same as the number of factors of 2⁵ × 3⁷ × 5⁵ × 7⁷
= 6×8×6×8
= 2304 Answer
(Q). How many factors of N = 2⁷ × 3⁷ × 5⁷ × 7⁷ ends with two zeros ?
Solution:-
In every factor 2² × 5² will be common
∴ required number of factor is same as the number of factors of 2⁵ × 3⁷ × 5⁵ × 7⁷
= 6×8×6×8
= 2304 Answer