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(Q). Find the number of trailing zeros at the end of 40 × 41 × 42 × 43 × ………..till 40 terms.

Solution:- 40 × 41 × 42 × 43 × …….. × 78 × 79

=

\frac{{79!}}{{39!}}
so the question has converted that we have to find the number of trailing zeros at the end of \frac{{79!}}{{39!}}

⇒ Now the number of trailing zeros at the end of 

79! & 39!55555579153071039188

Hence number of trailing zeros in the given equation = 18 – 8 = 10 Answer