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(Q). find the highest power of 12 in 1212!.
Solution:-
12 = 2² × 3

333121240413444143433310601∴ Highest power of 3 in 1212! = 60122222222222121260630315175371894210Hence highest power of 2 in 1212! = 12061206Hence highest power of 2² in 1212! = = 603

∴ Highest power of 12 in 1212! = minimum of above two values = 601 Answer