(Q). Find the FNZD in 20!×30!×40!×50!×60!
Solution:- In this case the number of trailing zeros in the product will be the summation of number of trailing zeros in individual terms. & FNZD of the product will be the multiplication of the FNZD’s of all the factorial terms.
Hence
∴ FNZD of product = 4×8×2×2×6
= 8 Answer