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                                                 Divisibility

Number & their classification:-

Natural Number(N):-   {1, 2, 3, 4, 5, …………….}
Whole Number(W):-  {0, 1, 2, 3, 4, 5, ……………. }
Integer(Z):-  {……. -4, -3, -2, -1, 0, 1, 2, 3, ……….}
Rational Number(Q):- \(\frac{1}{2}\), \(\frac{3}{7}\), \(\frac{1}{2}\), \(\frac{-6}{5}\), 0, +5, -130, ………..
Irrational Number:-  π, \(\sqrt 2 \), \(\sqrt 5 \), \(\sqrt 7 \), …………
Complex Number:-\(\sqrt { – 8} \), \(\sqrt { – 7} \), \(\sqrt { – 5} \), \(\sqrt { – 1} \), \(2 + \sqrt { – 5} \), \(3 + \sqrt { – 7} \), …………
Test for divisibility of numbers

Divisibility by 2:- If the last digit is an even number or it has 0 at the end then the number is divisible by 2.
Ex: 20, 50, 512, 678, 980324, 278

Divisibility by 3:- If the sum of the digits of the given number is divisible by 3 then the number is divisible by 3

Ex:- 513, 900, 87021, 2345Sum of digits991821

Divisibility by 4:- If the number formed by last two digits of a number is divisible by 4 then the number is divisible by 4.

Ex: -432, 500, 816, 512, 780030572

Divisibility by 5:- If the last digit of the given number is 0 or 5 then the number is divisible by 5.

Ex: -60, 5780, 6635, 78925, 7080900 or 5

Divisibility by 6:- If the given number is divisible by both 2 and 3 then the number is divisible by 6.

Ex: -8760, 23052 , 90070824ZeroEvenEvenSum of digits 21 12 30

Divisibility by 7:-

Method (1):
Take the last digit of the number an multiply it by 2.
Subtract the result from the rest of the number
Repeat the process if necessary until you get a small number.
If the result is 0 or multiple of 7, the original number is divisible by 7 otherwise, it is not.

Ex:- 6 1 9 1 5 8 4×286 1 9 1 5 0×2- 06 1 9 1 5×2- 106 1 8 1×2- 26 1 6×2- 1249Divisible by 7Hence given numberis divisible by 7 Answer

Method(2): Adding 5 times the last digit to the rest gives a multiple of 7. 

Ex:- 9 6 1 4 3 5 2 0 9×2-189 6 1 4 3 5 0 2×2- 49 6 1 4 3 4 6×2- 129 6 1 4 2 2×29 6 1 3 8- 4×2- 169 5 9 7×2- 149 4 1 5Divisible by 7Hence given numberis divisible by 7 Answer×2- 1084

Method(2): Adding 5 times the last digit to the rest gives a multiple of 7.

Ex:- 6 1 9 1 5 8 2×5+106 1 9 1 6 8×5+ 406 1 9 5 6×5+ 306 2 2 5×5+106 3 2×5+ 1073Not divisible by 7Hence given numberis divisible by 7 AnswerEx:- 9 6 1 4 3 5 2 0 9×5+109 6 1 4 3 5 6 5×5+ 259 6 1 4 3 8 1×5+ 5×5+159 6 6 0×509 6 6Divisible by 7Hence given numberis divisible by 7 Answer9 6 1 4 4 3×5+ 30126Ex:- 6 1 9 1 5 8 4×5+206 1 9 1 7 8×5+ 406 1 9 5 7×5+ 356 2 3 0×5+06 2 3×5+ 1577Divisible by 7Hence given numberis divisible by 7 Answer

Method(3):
Using three-digit pairs:-
⟶ Split the number into groups of three digits from right to left.
⟶ calculate the alternating sum of these groups
⟶ If the result is 0 or divisible by 7, the original number is divisible by 7.    

Ex: 6191584 961435209 9614352090+ 6 - 191 + 584 = 399+ 961 - 435 + 209 = 735Divisible by 7Divisible by 7Hence original numberis divisible by 7Hence original numberis divisible by 7++--= 343Divisible by 7Hence original numberis divisible by 7

Divisibility by 8:- If the number formed by the last three digits of the given number is divisible by 8 then the given number is divisible by 8.

Ex: 7512 67008 382616divisible by 8divisible by 8divisible by 8

Divisibility by 9: If the sum of digits of the given number is divisible by 9.

Ex: 23085 96327 1233Sum of digits18279

Divisibility by 10:- If the last digit of the number is 0.
Ex:   680         57320            4100850

Divisibility by 11:- If the difference of the sum of its digits in odd places and the sum of its digits in even places is either 0 or multiplee by 11.

Ex: 3 6 2 3 415432+9+9-0Number is divisible by 116 2 9 1 3 1 8264++-22Hence number is divisible by 11divisible by 11

Divisibility by 13:-
Method (1):
 Add 4 times the last digit to the rest. The result must be 0 or divisible by 13.

Ex:- 7 5 9 2×4+87 6 7×4+ 28104Divisible by 13Ex:- 3 4 5 4 4×4+163 4 7 0×403 4 7Divisible by 13×42852

Method(2): Subtract 9 times the last ddigit from the rest. The result must be 0 or divisible by 13.

Ex:- 6 4 8 3 7 5×9- 456 4 7 9 2×9- 186 4 6 1×9- 96 3 7×9- 630ZeroHence number is divisible by 13Ex:- 1 2 3 3 8 3 5 2×9- 181 2 3 3 8 1 7×9- 631 2 3 3 1 8×9- 721 2 2 5 9×9- 81Divisible by 131 1 4 4×93678Hence number is divisible by 13

Method(3):
⟶ Split the number into groups of three from right to left
⟶ calculate the alternating sum of these groups
⟶ If the result is 0 or divisible by 13, the original number is divisible by 13

Ex: 7660068585++--= - 7 + 660 - 068 + 585= 1170Divisible by 13∴ original number is divisible by 13

Divisibility by 17:-
Method(1):
 Subtract 5 times the last digit from the rest. The result must be 0 or divisible by 17.

Ex:- 1 8 2 2 1 4 5×5- 251 8 2 1 8 9×5- 451 8 1 7 3×5- 151802Divisible by 17Hence original number isdivisible by 17

Method(2): Add 12 times the last digit to the rest. The result must be 0 or divisible by 17.

Ex:- 1 8 2 2 1 4 5×12+ 601 8 2 2 7 4×12+ 481 8 2 7 5×12601 8 8 7Divisible by 17Hence original number isdivisible by 17×1284272

Some General Property of Divisibility:-

● If a number x is divisible by y , then any number divisible by x, will also be divisible by y and all the factors of y.
Ex: The number 72 is divisible by 6. Thus any number that is divisible by 72, will also be divisible by 6 an also factors of 6 i.e. by 2 and 3.
● If a number x is divisible by two or more than two co-prime numbers then x is also divisible by the product  of those numbers.
Ex:- The number 2040 is divisible by 3, 8, 17 that are co-prime to each other so 2040 will also be divisible by 3 × 8 = 24, 3 × 17 = 51, 8 × 17 = 136
● If two numbers x and y are divisible by ‘p’, then their sum x + y is also divisible by p.
Ex:- The number 138 and 312 are both divisible by 6. Thus their sum = 138 + 312  = 450 will also be divisible by 6.
● If any number is written 6 times like 111111, 222222, 777777 etc, it will be exactly divisible by 7, 11, 13, 37 & 1001
● Any number written like 2727, 3535, 2929 will be divisible by 101.

(a - b)n is even number this number is divisible by (a - b) & (a + b)n is odd number this number is divisible by (a + b)

(aⁿ + bⁿ) n is odd then this number is divisible by (a + b)
(aⁿ + bⁿ) n is even then it can not be determined.
● A six digit number is formed by repeating a three digit number; for example 257257, 689689, 649649 then this form of number is exactly divisible by 7, 11, 13, 1001.
● If a is divisible by b then ac is also divisible by b.
● If a is divisible by b and b is divisible by c then a is divisible by c.
● If two numbers a & b are divisible by a third number c then (a – b) is also divisible by c.

Successive Division:- successive division, also known as repeated division, involves dividing a number by a sequence of divisors, where quotient from one divisor becomes the dividend for the next. This process continues until a quotient of zero is obtained.

dR×(d×Q + R) = Q(d×Q + R)NumberdR×(d×Q + R) = QdR×(d×Q + R) = QdR×Q ⩽ Rfor least number put Q = 0

Ex:- Successive division of a number by 2 3, 5 and 7 gives remainder 1, 4, 0 and 5 respectively. What will be the sum of remainders if same number is divided by 7, 5, 3 and 2 successively ?
Sol:

2 1×+793 4×+255 0×+57 5×+0159Number
7 22 51595 4 23 1 12 0 1Sum = 9 Answer

(Q). A certain number when successively divided by 4, 5 and 7 leaves remainder 2, 3, 4 respectively. Find such least number
(i) 374     (ii) 514     (iii) 234     (iv) 92
Sol:

4 2×+235 3×+ 47 4×+04 2×+58945 3×+117 4×+1234option (iii)Answer

● Product of n consecutive number is always divisible by n!
Ex: n(n + 1)(n + 2)(n + 3)(n + 4) ⟶ divisible by 5!
(n – 3)(n – 2)(n – 1)(n)(n + 1)(n + 2) ⟶ divisible by 6!

(Q). n² – n is always divisible by which number.
Sol:
(n – 1)(n)(n + 1)
⟶ divisible by 3! = 6      Answer