(Q). If k! is not divisible by 1155 then find the maximum value of k (i) 11(ii) 17(iii) 10(iv) 7 Solution:- Since 1155 = 3×5×7×11if we take k as 11 or above then k! will be completely divisible by 1155...
(Q). If p = x¹⁰⁰⁰(1000!) & p is divisible by 10¹⁰⁰⁰. then what would be the minimum number of zeros at the end of p. Solution:- first find number of trailing zeros in...
(Q). If p = (x{!^{y{!^{z!}}}}) & p is a single digit number then find the possible value of p.Solution:- ➠ if x = 0 or 1 ⇒ x! = 1 then y & z can take any value & value of p will be = 1. ➠ if x = 2 ⇒ x! = 2if y = 0 or 1 ⇒ y! = 1 then z can take any value...
(Q). An expression is given below:N = 1! + 2! + 3! + 4! + 5! + ………. + 99! + 100!(i) Find the unit digit of N(ii) Find the last two digit of N(iii) What will be the remainder when N is divided by 7....
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