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Let Tₙ be the number of all possible triangles formed by joining vertices of an n – sided regular polygon. If Tₙ₊₁ – Tₙ = 10, then what will be the value of n

(Q). Let Tₙ be the number of all possible triangles formed by joining vertices of an n – sided regular polygon. if Tₙ₊₁ – Tₙ = 10, then what will be the value of n? Solution:-  As per the given conditionⁿ⁺¹C₃ – ⁿC₃ = 10we know that  ⁿCᵣ + ⁿCᵣ ₋ ₁ = ⁿ...

The sides AB, BC & CA of a triangle ABC have 3, 4 and 5 interior points respectively on them.The number of triangles that can be constructed using these interior points as vertices will be?

we have following cases in this question:-case (i): if one point is selected from each side then number of triangle is = 3×4×5 = 60case (ii):  if one point is selected from one side and 2 points from another side then number of ways is= ³C₂×(4 + 5) + ⁴C₂×(5+3)...