(Q). A three digit number xyz is such that x + y + z = 26. Then find the sum of all possible values of x!.y!.z!.
Solution:-
x + y + z = 26
9 9 8 ⇾ 998, 989, 899
∴ there will be three such numbers.
9!.9!.8! + 9!.8!.9! + 8!.9!.9!
= 3.9!.9!.8! Answer