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                               Permutation & Combination

                                                                 PNC

Introduction of selection/combination:-

Let us assume that Suresh has 5 friends A, B, C, D, E and he want to invite 2 of them for a party.
So the question is how many ways he can invite 2 friends out of 5 friends.
First Let us do it manually 
A        B        C        D        E
Number of ways 
(A, B)        (A, C)        (A, D)        (A, E)
(B, C)        (B, D)        (B, E)
(C, D)        (C, E)
(D,E)
= 10 ways
Since here we are to select 2 out of 5 values which we can do manually but if these numbers ↑ then it will become difficult to do it manually. So we will do it with the help of a formula.
⦿ Number of ways of selecting ‘r’ articles from ‘n’ distinct article is :-

C =

Example:- Suresh has a party at his home. He has 12 friends & want to invite only 3 of them. In how many ways he can do this?
Solution:-

\begin{array}{l} ^{12}{C_3} = \frac{{12!}}{{3! \times 9!}}\\  = \frac{{12 \times 11 \times 10 \times 9}}{{3 \times 2}} \end{array}

= 220 ways Answer

⦿ Number of ways of selecting ‘r’ articles from ‘n’ distinct articles if ‘k’ article is always included :-

Example:- In how many ways kapil can call 5 of his 12 friends if amit & ankit are always included?
Solution:-

¹²⁻²C₅₋₂
= ¹⁰C₃ 
= 120 Answer